Cincinnati Open: Zverev falls in round of 16 to American Paul
German third seed Alexander Zverev suffered a surprise three-set loss to American Tommy Paul in the round of 16 at the Cincinnati Open. Zverev had entered the match as the bookmakers' favorite but failed to convert a match point in the second set.
Germany's top player Alexander Zverev, currently ranked third in the ATP standings, lost overnight to American Tommy Paul, a former world number eight. The match finished 6:4, 6:7, 4:6 in the American's favor.
Before the match, bookmakers considered Zverev the clear favorite, offering odds of 1.35 on his victory. However, the contest swung in Paul's direction. In the second-set tiebreak, Zverev came within a point of victory, leading 6-5 and holding a match point, but ultimately lost the tiebreak 6-8. In the third set, Zverev again took the lead at 4:2, but went on to lose the set 4:6, and with it the match.
Match statistics
Zverev trailed in several statistical categories: he won 53% of points on his second serve compared to Paul's 61%, and lost the overall points count 98:100. Paul also converted break points more efficiently, winning 2 of 3 compared to Zverev's 2 of 5. Zverev hit more aces (14 to 9) but also committed more double faults (9 to 1). In unforced errors, the German made 46 compared to Paul's 34.
With this defeat, the head-to-head record between the two players now stands at 1-3 in Paul's favor. This was Zverev's 11th appearance at the Cincinnati tournament, where his best result remains the title he won in 2021.
Other round of 16 results
Elsewhere in the round of 16, Australian Alex de Minaur lost to Frenchman Arthur Fils 3:6, 4:6, while Italy's Flavio Cobolli defeated Spaniard Roberto Bautista Agut's compatriot Roberto Carballes Baena—reported in the source as Rafael Jodar—6:3 after a three-set battle 4:6, 7:6, 6:3.
